What is the inverse of f(x)=(1/2 x-1)^2-2 ?

The inverse of f(x)=(1/2 x-1)^2-2 is 2sqrt(x+2)+2,-2sqrt(x+2)+2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=(1/2 x-1)^2-2

inverse

f (x) = (\frac{1}{2} x - 1)^{2} - 2

2 x + 2 + 2, - 2 x + 2 + 2

Solution steps

y = (\frac{1}{2} x - 1)^{2} - 2

Replace

x

with

y

x = (\frac{1}{2} y - 1)^{2} - 2

Solve for

y, x = (\frac{1}{2} y - 1)^{2} - 2

2 x + 2 + 2, - 2 x + 2 + 2

\frac{5}{x ^{2} + 1}

f (x) = - x^{2} - 3

f (x) = 6 - x

f (x) = 3 x^{2} + 6

Y = 2 X^{2} - 3

What is the inverse of f(x)=(1/2 x-1)^2-2 ?
The inverse of f(x)=(1/2 x-1)^2-2 is 2sqrt(x+2)+2,-2sqrt(x+2)+2