What is the domain of f(x)=(sqrt(9-x^2))/(sqrt(x+1)) ?

The domain of f(x)=(sqrt(9-x^2))/(sqrt(x+1)) is -1<x<= 3

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domain of f(x)=(sqrt(9-x^2))/(sqrt(x+1))

domain

f (x) = \frac{9 - x ^{2}}{x + 1}

- 1 < x \leq 3

Interval Notation

(- 1, 3]

Solution steps

Find non-negative values for radicals:

- 1 \leq x \leq 3

Find undefined (singularity) points:

x = - 1

Combine real regions and undefined points for final function domain

- 1 < x \leq 3

f (x) = \frac{3 x + 4}{2 x - 3}

f (x) = \frac{x ^{2} - 16}{x + 4}

f (x) = x - 1

\frac{1}{x ^{4} - 10 x ^{2} + 9}

\frac{x}{4 x ^{2} + 3 x - 1}

What is the domain of f(x)=(sqrt(9-x^2))/(sqrt(x+1)) ?
The domain of f(x)=(sqrt(9-x^2))/(sqrt(x+1)) is -1<x<= 3