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Popular >

inflection f(x)=x(x^2-4)

Solution

inflection points

f (x) = x (x^{2} - 4)

Solution

(0, 0)

Solution steps

f^{''} (x) = 6 x

Find intervals:

Concave Downward

: - \infty < x < 0,

Concave Upward

: 0 < x < \infty

Plug

x = 0

into

x (x^{2} - 4) : 0

(0, 0)

Popular Examples

critical y=2+9x+3x^2-x^3 critical points

y = 2 + 9 x + 3 x^{2} - x^{3}

inverse of 3sqrt(9(x-1))inverse

3 9 (x - 1)

range of (3x-4)/(x+2)range

\frac{3 x - 4}{x + 2}

parallel 3x-4y=2,(1/3 ,-1)parallel

3 x - 4 y = 2, (\frac{1}{3}, - 1)

inverse of f(x)= 4/(x-4)inverse

f (x) = \frac{4}{x - 4}

Frequently Asked Questions (FAQ)

What is the inflection f(x)=x(x^2-4) ?
The inflection f(x)=x(x^2-4) is (0,0)