What is the inverse of f(x)=1650((1.022))^t ?

The inverse of f(x)=1650((1.022))^t is (ln(t/(1650)))/(ln(1.022))

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inverse of f(x)=1650((1.022))^t

inverse

f (x) = 1650 ((1.022))^{t}

\frac{ln ( \frac{t}{1650} )}{ln ( 1.022 )}

Solution steps

x = 1650 \cdot 1.02 2^{t}

Replace

t

with

x

t = 1650 \cdot 1.02 2^{x}

Solve for

x, t = 16501.02 2^{x}

\frac{ln ( \frac{t}{1650} )}{ln ( 1.022 )}

\frac{5}{x}

f (x) = \frac{x - 8}{x ^{2} + x - 72}

f (x) = \frac{( x + 4 )}{x - 3}

f (x) = x^{2}

\frac{1}{2} y + 2 = 0

What is the inverse of f(x)=1650((1.022))^t ?
The inverse of f(x)=1650((1.022))^t is (ln(t/(1650)))/(ln(1.022))