What is the inverse of f(x)=sin(ln(x^3-2)) ?

The inverse of f(x)=sin(ln(x^3-2)) is cube root of e^{arcsin(x)}+2

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inverse of f(x)=sin(ln(x^3-2))

inverse

f (x) = sin (ln (x^{3} - 2))

Solution steps

sin (a) = b \Rightarrow a = arcsin (b)

ln (x^{3} - 2) = arcsin (y)

Solve for

x, ln (x^{3} - 2) = arcsin (y)

Substitute

y = x

\frac{x - 8}{7}

f (x) = x^{4} - 8 x^{2} + 3

0.8 x^{2} + \frac{72}{x}

(4, - 5), (- 1, 7)

f (x) = \frac{1}{1 - e ^{x}}

What is the inverse of f(x)=sin(ln(x^3-2)) ?
The inverse of f(x)=sin(ln(x^3-2)) is cube root of e^{arcsin(x)}+2