What is the extreme f(x)=(ln(x))/(sqrt(x)) ?

The extreme f(x)=(ln(x))/(sqrt(x)) is Maximum(e^2, 2/e)

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extreme f(x)=(ln(x))/(sqrt(x))

extreme points

f (x) = \frac{ln ( x )}{x}

Maximum (e^{2}, \frac{2}{e})

Solution steps

f^{'} (x) = \frac{2 - ln ( x )}{2 x x}

Find intervals:

Increasing

: 0 < x < e^{2},

Decreasing

: e^{2} < x < \infty

Plug

x = e^{2}

into

\frac{ln ( x )}{x} : \frac{2}{e}

Maximum (e^{2}, \frac{2}{e})

m = - 3

(6, - 6), (2, 4)

f (x) = \frac{2 x - 3}{x + 4}

\frac{( x - 6 )}{( x + 5 )}

f (x) = 5 x^{7} + 2 x^{3} + 6

What is the extreme f(x)=(ln(x))/(sqrt(x)) ?
The extreme f(x)=(ln(x))/(sqrt(x)) is Maximum(e^2, 2/e)