What is the domain of f(x)= 2/((sqrt(2x-5))) ?

The domain of f(x)= 2/((sqrt(2x-5))) is x> 5/2

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domain of f(x)= 2/((sqrt(2x-5)))

domain

f (x) = \frac{2}{( 2 x - 5 )}

x > \frac{5}{2}

Interval Notation

(\frac{5}{2}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq \frac{5}{2}

Find undefined (singularity) points:

x = \frac{5}{2}

Combine real regions and undefined points for final function domain

x > \frac{5}{2}

f (x) = \frac{( 2 x + 1 )}{1 - x}

f (x) = y^{2}

f (x) = \frac{- x + 5}{2}

- \frac{2}{x}

f (x) = x^{2} + 16 x + 61

What is the domain of f(x)= 2/((sqrt(2x-5))) ?
The domain of f(x)= 2/((sqrt(2x-5))) is x> 5/2