What is the critical f(x)=xsqrt(25-x^2) ?

The critical f(x)=xsqrt(25-x^2) is x=-5,x=-5/(sqrt(2)),x= 5/(sqrt(2)),x=5

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critical f(x)=xsqrt(25-x^2)

critical points

f (x) = x 25 - x^{2}

x = - 5, x = - \frac{5}{2}, x = \frac{5}{2}, x = 5

Solution steps

x 25 - x^{2}

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{5}{2}, x = \frac{5}{2}, x = - 5, x = 5

Identify critical points not in

f (x)

domain

Domain of

x 25 - x^{2} : - 5 \leq x \leq 5

All critical points are in domain

x = - 5, x = - \frac{5}{2}, x = \frac{5}{2}, x = 5

y = x^{2} + 5

(\frac{4}{10})^{x}

y = - 2 lo g_{2} (x)

\frac{x}{9 x - 8}

\frac{6 x}{x - 1}

What is the critical f(x)=xsqrt(25-x^2) ?
The critical f(x)=xsqrt(25-x^2) is x=-5,x=-5/(sqrt(2)),x= 5/(sqrt(2)),x=5