What is the domain of (x+1)/(sqrt(x^2+1)) ?

The domain of (x+1)/(sqrt(x^2+1)) is -infinity <x<infinity

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domain of (x+1)/(sqrt(x^2+1))

domain

\frac{x + 1}{x ^{2} + 1}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find non-negative values for radicals:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = \frac{1}{x - 7}

(1.1) (2.2)

x^{2} + 8 x + 16

f (x) = \frac{1}{3} sin (x + \frac{π}{4})

f (x) = \frac{x - 3}{x + 2}

What is the domain of (x+1)/(sqrt(x^2+1)) ?
The domain of (x+1)/(sqrt(x^2+1)) is -infinity <x<infinity