What is the domain of f(x)=((x+3))/(x-7) ?

The domain of f(x)=((x+3))/(x-7) is x 7

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domain of f(x)=((x+3))/(x-7)

domain

f (x) = \frac{( x + 3 )}{x - 7}

x < 7 or x > 7

Interval Notation

(- \infty, 7) \cup (7, \infty)

Solution steps

Find undefined (singularity) points:

x = 7

The function domain

x < 7 or x > 7

f (x) = \frac{2 x - 1}{x ^{2} + 9 x}

X + 3

(- 8, - 4), (2, 2)

- \frac{4}{3} x + 5

f (x) = x^{4} - 16 x^{2}

What is the domain of f(x)=((x+3))/(x-7) ?
The domain of f(x)=((x+3))/(x-7) is x<7\lor x>7