What is the domain of f(x)=sqrt(x^2+2) ?

The domain of f(x)=sqrt(x^2+2) is -infinity <x<infinity

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domain of f(x)=sqrt(x^2+2)

domain

f (x) = x^{2} + 2

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find non-negative values for radicals:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = - (x + 5)^{2} + 3

g (x) = \frac{x + 5}{2}

(- 2) (4.9)

f (x) = x^{(\frac{1}{x})}

x^{3} + x^{2} - 9 x - 9

What is the domain of f(x)=sqrt(x^2+2) ?
The domain of f(x)=sqrt(x^2+2) is -infinity <x<infinity