What is the inverse of f(x)=((x+18))/((x-17)) ?

The inverse of f(x)=((x+18))/((x-17)) is (18+17x)/(x-1)

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inverse of f(x)=((x+18))/((x-17))

inverse

f (x) = \frac{( x + 18 )}{( x - 17 )}

\frac{18 + 17 x}{x - 1}

Solution steps

y = \frac{x + 18}{x - 17}

Replace

x

with

y

x = \frac{y + 18}{y - 17}

Solve for

y, x = \frac{y + 18}{y - 17}

\frac{18 + 17 x}{x - 1}

x = - \frac{2}{3} y - 2

f (x) = x^{3} - 6 x^{2} + 9 x + 4

f (x) = \frac{( - 3 )}{( ∣ x + 2 ∣ )}

f (x) = \frac{x ^{2} - 1}{x ^{2} + 5 x + 6}

f (x) = \frac{5 x ^{2} + 4}{x ^{2} + 3 x - 10}

What is the inverse of f(x)=((x+18))/((x-17)) ?
The inverse of f(x)=((x+18))/((x-17)) is (18+17x)/(x-1)