What is the inverse of f(x)=((3x+1))/((x-2)) ?

The inverse of f(x)=((3x+1))/((x-2)) is (1+2x)/(x-3)

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inverse of f(x)=((3x+1))/((x-2))

inverse

f (x) = \frac{( 3 x + 1 )}{( x - 2 )}

\frac{1 + 2 x}{x - 3}

Solution steps

y = \frac{3 x + 1}{x - 2}

Replace

x

with

y

x = \frac{3 y + 1}{y - 2}

Solve for

y, x = \frac{3 y + 1}{y - 2}

\frac{1 + 2 x}{x - 3}

f (x) = x^{3} - x^{2} + x - 1

x + 2 y = 2

π - 3 arcsin (2 x - 1)

y = - \frac{1}{3} x + 9

f (x) = t - 4

What is the inverse of f(x)=((3x+1))/((x-2)) ?
The inverse of f(x)=((3x+1))/((x-2)) is (1+2x)/(x-3)