What is the inverse of f(x)=x^2-4,x<= 0 ?

The inverse of f(x)=x^2-4,x<= 0 is sqrt(x+4),-sqrt(x+4)

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inverse of f(x)=x^2-4,x<= 0

inverse

f (x) = x^{2} - 4, x \leq 0

x + 4, - x + 4

Solution steps

y = x^{2} - 4

Replace

x

with

y

x = y^{2} - 4

Solve for

y, x = y^{2} - 4

x + 4, - x + 4

f (x) = 11101000011

f (x) = (\frac{6}{5})^{- x}

f (x) = ln (x + 5)

f (x) = e^{- 2.5 x^{2}}

3 x^{2} + 2 x + 1

What is the inverse of f(x)=x^2-4,x<= 0 ?
The inverse of f(x)=x^2-4,x<= 0 is sqrt(x+4),-sqrt(x+4)