What is the critical f(x)=(x^3)/3-4x ?

The critical f(x)=(x^3)/3-4x is x=-2,x=2

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critical f(x)=(x^3)/3-4x

critical points

f (x) = \frac{x ^{3}}{3} - 4 x

x = - 2, x = 2

Solution steps

\frac{x ^{3}}{3} - 4 x

Find where

f^{'} (x)

is equal to zero or undefined

x = - 2, x = 2

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{3}}{3} - 4 x : - \infty < x < \infty

All critical points are in domain

x = - 2, x = 2

f (x) = \frac{( x + 3 )}{4}

y = \frac{3}{x + 4} + 2

(- 1, 1), (- 4, - 2)

5 sin (∣ x ∣)

\frac{1 - 3 x}{5 + x}