What is the range of f(x)=sqrt(2x-8) ?

The range of f(x)=sqrt(2x-8) is f(x)>= 0

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range of f(x)=sqrt(2x-8)

range

f (x) = 2 x - 8

f (x) \geq 0

Interval Notation

[0, \infty)

Solution steps

The range of an radical function of the form

c a x + b + k

f (x) \geq k

k = 0

f (x) \geq 0

f (x) = x + 2 y = 5

sin (x) + cos^{2} (x)

\frac{ln ( x - 2 )}{( x - 2 ) ^{2}}

y = x^{2} - 8 x + 3

(6.6) (0)