What is the parity y=(tan(-arctan(x^2)+2c))/2 ?

The parity y=(tan(-arctan(x^2)+2c))/2 is Even

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parity y=(tan(-arctan(x^2)+2c))/2

parity

y = \frac{tan ( - arctan ( x ^{2} ) + 2 c )}{2}

Even

Solution steps

f (- x) : \frac{sin ( 2 c ) - x ^{2} cos ( 2 c )}{2 cos ( 2 c ) + 2 x ^{2} sin ( 2 c )}

- f (x) : - \frac{tan ( - arctan ( x ^{2} ) + 2 c )}{2}

Check parity of

\frac{tan ( - arctan ( x ^{2} ) + 2 c )}{2}

Check if Even:

True

Check if Odd:

False

Even

1 0^{- x}

f (x) = e^{x - 4}

(4), (- 2)

- 4 x = y^{2}

f (x) = - 2 x^{2}

What is the parity y=(tan(-arctan(x^2)+2c))/2 ?
The parity y=(tan(-arctan(x^2)+2c))/2 is Even