What is the domain of f(x)= 1/(sqrt(x^2-2x)) ?

The domain of f(x)= 1/(sqrt(x^2-2x)) is x 2

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domain of f(x)= 1/(sqrt(x^2-2x))

domain

f (x) = \frac{1}{x ^{2} - 2 x}

x < 0 or x > 2

Interval Notation

(- \infty, 0) \cup (2, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 0 or x \geq 2

Find undefined (singularity) points:

x = 2, x = 0

Combine real regions and undefined points for final function domain

x < 0 or x > 2

f (x) = \frac{x ^{2} - x - 2}{x - 2}

\frac{3}{4} x + 7

y = \frac{( - 3 x - 7 )}{( x - 1 )}

(- 1, - 5), (2, 1)

f (x) = - 2 x - 2 + 6

What is the domain of f(x)= 1/(sqrt(x^2-2x)) ?
The domain of f(x)= 1/(sqrt(x^2-2x)) is x<0\lor x>2