What is the range of f(x)=log_{10}(1/x) ?

The range of f(x)=log_{10}(1/x) is -infinity <f(x)<infinity

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

range of f(x)=log_{10}(1/x)

range

f (x) = lo g_{10} (\frac{1}{x})

- \infty < f (x) < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function range is the combined domain of the inverse functions

Find the inverse function(s) of:

lo g_{10} (\frac{1}{x})

Inverse of

lo g_{10} (\frac{1}{x}) : \frac{1}{1 0 ^{x}}

\frac{1}{1 0 ^{x}}

Find the domain of each inverse function

Domain of

\frac{1}{1 0 ^{x}} : - \infty < x < \infty

Combine the intervals

- \infty < f (x) < \infty

- 2 x^{2} + 2 x

\frac{1 - x ^{2}}{2 x + 1}

x^{3} + 8

x = 1

f (x) = 3 x + 1

What is the range of f(x)=log_{10}(1/x) ?
The range of f(x)=log_{10}(1/x) is -infinity <f(x)<infinity