What is the domain of f(x)= 1/(sqrt(x-7)) ?

The domain of f(x)= 1/(sqrt(x-7)) is x>7

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domain of f(x)= 1/(sqrt(x-7))

domain

f (x) = \frac{1}{x - 7}

x > 7

Interval Notation

(7, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 7

Find undefined (singularity) points:

x = 7

Combine real regions and undefined points for final function domain

x > 7

f (x) = x - x^{2}

f (x) = 5 (x - 2)

y = ∣ x - 3 ∣ + 2

f (x) = x^{2} + 8 x + 16

g (x) = \frac{3 x - 2}{2}

What is the domain of f(x)= 1/(sqrt(x-7)) ?
The domain of f(x)= 1/(sqrt(x-7)) is x>7