What is the inverse of f(x)= 1/5 x^2-1 ?

The inverse of f(x)= 1/5 x^2-1 is sqrt(5x+5),-sqrt(5x+5)

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inverse of f(x)= 1/5 x^2-1

inverse

f (x) = \frac{1}{5} x^{2} - 1

5 x + 5, - 5 x + 5

Solution steps

y = \frac{1}{5} x^{2} - 1

Replace

x

with

y

x = \frac{1}{5} y^{2} - 1

Solve for

y, x = \frac{1}{5} y^{2} - 1

5 x + 5, - 5 x + 5

f (x) = \frac{3}{x + 2}

f (x) = \frac{1}{10 2 x + 12 - 20}

f (x) = x^{3} - 12 x + 20

- \frac{3}{4}

m = \frac{3}{7}

What is the inverse of f(x)= 1/5 x^2-1 ?
The inverse of f(x)= 1/5 x^2-1 is sqrt(5x+5),-sqrt(5x+5)