What is the domain of f(x)= 1/(10sqrt(2x+12)-20) ?

The domain of f(x)= 1/(10sqrt(2x+12)-20) is -6 -4

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domain of f(x)= 1/(10sqrt(2x+12)-20)

domain

f (x) = \frac{1}{10 2 x + 12 - 20}

- 6 \leq x < - 4 or x > - 4

Interval Notation

[- 6, - 4) \cup (- 4, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 6

Find undefined (singularity) points:

x = - 4

Combine real regions and undefined points for final function domain

- 6 \leq x < - 4 or x > - 4

f (x) = x^{3} - 12 x + 20

- \frac{3}{4}

m = \frac{3}{7}

\frac{e ^{x}}{x ^{2}}

f (x) = x^{3} - 27 x + 4

What is the domain of f(x)= 1/(10sqrt(2x+12)-20) ?
The domain of f(x)= 1/(10sqrt(2x+12)-20) is -6<= x<-4\lor x>-4