What is the extreme f(x)=2x^3-24x-4 ?

The extreme f(x)=2x^3-24x-4 is Maximum(-2,28),Minimum(2,-36)

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extreme f(x)=2x^3-24x-4

extreme points

f (x) = 2 x^{3} - 24 x - 4

Maximum (- 2, 28), Minimum (2, - 36)

Solution steps

f^{'} (x) = 6 x^{2} - 24

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = - 2

into

2 x^{3} - 24 x - 4 : 28

Maximum (- 2, 28)

Plug

x = 2

into

2 x^{3} - 24 x - 4 : - 36

Minimum (2, - 36)

Maximum (- 2, 28), Minimum (2, - 36)

f (x) = \frac{4 + x}{2 - x}

f (x) = 12

5 x + 4 y = 1

- \frac{7 x}{x - 6}

What is the extreme f(x)=2x^3-24x-4 ?
The extreme f(x)=2x^3-24x-4 is Maximum(-2,28),Minimum(2,-36)