What is the asymptotes of f(x)=(2x^2+x-18)/(x^2-9) ?

The asymptotes of f(x)=(2x^2+x-18)/(x^2-9) is Vertical: x=-3,x=3,Horizontal: y=2

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asymptotes of f(x)=(2x^2+x-18)/(x^2-9)

asymptotes

f (x) = \frac{2 x ^{2} + x - 18}{x ^{2} - 9}

Vertical : x = - 3, x = 3, Horizontal : y = 2

Solution steps

Vertical asymptotes of

\frac{2 x ^{2} + x - 18}{x ^{2} - 9} : x = - 3, x = 3

Horizontal Asymptotes of

\frac{2 x ^{2} + x - 18}{x ^{2} - 9} : y = 2

Slant Asymptotes of

\frac{2 x ^{2} + x - 18}{x ^{2} - 9} :

None

Vertical : x = - 3, x = 3, Horizontal : y = 2

f (x) = \frac{x}{1 - ln ( x - 6 )}

\frac{3 x}{x ^{2} - 4}

f (x) = \frac{- 1}{2 3 - x}

f (x) = 2 sin (x)

f (x) = 8 x^{3}

What is the asymptotes of f(x)=(2x^2+x-18)/(x^2-9) ?
The asymptotes of f(x)=(2x^2+x-18)/(x^2-9) is Vertical: x=-3,x=3,Horizontal: y=2