What is the inverse of y=3(x+2)^2-6 ?

The inverse of y=3(x+2)^2-6 is sqrt((x+6)/3)-2,-sqrt((x+6)/3)-2

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inverse of y=3(x+2)^2-6

inverse

y = 3 (x + 2)^{2} - 6

\frac{x + 6}{3} - 2, - \frac{x + 6}{3} - 2

Solution steps

y = 3 (x + 2)^{2} - 6

Replace

x

with

y

x = 3 (y + 2)^{2} - 6

Solve for

y, x = 3 (y + 2)^{2} - 6

\frac{x + 6}{3} - 2, - \frac{x + 6}{3} - 2

5 x + 6 y = - 36

x^{2} - 4 x - 12

m = - 3, (2, - 2)

f (x) = \frac{- 14 + x}{6}

f (x) = \frac{2 x}{x - 6} - \frac{x}{x + 2}

What is the inverse of y=3(x+2)^2-6 ?
The inverse of y=3(x+2)^2-6 is sqrt((x+6)/3)-2,-sqrt((x+6)/3)-2