What is the domain of f(x)=sqrt(8-4x) ?

The domain of f(x)=sqrt(8-4x) is x<= 2

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domain of f(x)=sqrt(8-4x)

domain

f (x) = 8 - 4 x

x \leq 2

Interval Notation

(- \infty, 2]

Solution steps

Find non-negative values for radicals:

x \leq 2

The function domain

x \leq 2

f (x) = \frac{x ^{2} + 3 x - 4}{x ( x ^{2} - 5 )}

3 x - y = 2

f (x) = - x + 5

f (x) = \frac{1 - 3 x ^{3}}{2 x ^{3} - 6 x + 2}

\frac{3}{x - 1}