What is the domain of f(x)= 6/(sqrt(x^2-16)) ?

The domain of f(x)= 6/(sqrt(x^2-16)) is x 4

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domain of f(x)= 6/(sqrt(x^2-16))

domain

f (x) = \frac{6}{x ^{2} - 16}

x < - 4 or x > 4

Interval Notation

(- \infty, - 4) \cup (4, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 4 or x \geq 4

Find undefined (singularity) points:

x = 4, x = - 4

Combine real regions and undefined points for final function domain

x < - 4 or x > 4

(1, - 1), (3, 3)

f (x) = 3 + 2 + x

y - 7 = 1 (x - 1)

q (x) = 5 x - \frac{( 3 + 5 x )}{5}

f (x) = 7 (x - 8)^{3}

What is the domain of f(x)= 6/(sqrt(x^2-16)) ?
The domain of f(x)= 6/(sqrt(x^2-16)) is x<-4\lor x>4