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Popular >

range of sin(x)

Solution

range

sin (x)

Solution

- 1 \leq f (x) \leq 1

+1

Interval Notation

[- 1, 1]

Solution steps

The range of the basic

sin

function is

- 1 \leq sin (x) \leq 1

- 1 \leq sin (x) \leq 1

Therefore the range is

- 1 \leq f (x) \leq 1

Popular Examples

inverse of f(x)=((x-4))/(x+4)inverse

f (x) = \frac{( x - 4 )}{x + 4}

symmetry 4x^2-8y^2=5 symmetry

4 x^{2} - 8 y^{2} = 5

inverse of y=2*log_{7}(3x-39)inverse

y = 2 \cdot lo g_{7} (3 x - 39)

inverse of 1/2 x+1 inverse

\frac{1}{2} x + 1

inverse of f(x)=\sqrt[3]{(x-2)}+5 inverse

Frequently Asked Questions (FAQ)

What is the range of sin(x) ?
The range of sin(x) is -1<= f(x)<= 1