What is the inverse of y=2*log_{7}(3x-39) ?

The inverse of y=2*log_{7}(3x-39) is (7^{x/2}+39)/3

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inverse of y=2*log_{7}(3x-39)

inverse

y = 2 \cdot lo g_{7} (3 x - 39)

\frac{7 ^{\frac{x}{2}} + 39}{3}

Solution steps

y = 2 lo g_{7} (3 x - 39)

Replace

x

with

y

x = 2 lo g_{7} (3 y - 39)

Solve for

y, x = 2 \cdot lo g_{7} (3 y - 39)

\frac{7 ^{\frac{x}{2}} + 39}{3}

\frac{1}{2} x + 1

f (x) = \frac{x ^{2} + 10 x + 24}{2 x + 8}

y = x^{3} + 1

3 + 3 x

What is the inverse of y=2*log_{7}(3x-39) ?
The inverse of y=2*log_{7}(3x-39) is (7^{x/2}+39)/3