What is the domain of f(x)= x/(sqrt(4-x^2)) ?

The domain of f(x)= x/(sqrt(4-x^2)) is -2<x<2

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domain of f(x)= x/(sqrt(4-x^2))

domain

f (x) = \frac{x}{4 - x ^{2}}

- 2 < x < 2

Solution steps

Find non-negative values for radicals:

- 2 \leq x \leq 2

Find undefined (singularity) points:

x = 2, x = - 2

Combine real regions and undefined points for final function domain

- 2 < x < 2

f (x) = \frac{7}{x ^{2} - 2 x - 24}

f (x) = ln (\frac{x + 1}{x + 2})

f (x) = \frac{x ^{2} - 9}{x ^{2} - 4}

f (x) = \frac{x + 1}{x - 4}

f (x) = \frac{x ^{3}}{x ^{2} - 1}

What is the domain of f(x)= x/(sqrt(4-x^2)) ?
The domain of f(x)= x/(sqrt(4-x^2)) is -2<x<2