What is the range of tan(2θ-(11pi)/6)-1 ?

The range of tan(2θ-(11pi)/6)-1 is -infinity <f(θ)<infinity

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range of tan(2θ-(11pi)/6)-1

range

tan (2 θ - \frac{11 π}{6}) - 1

- \infty < f (θ) < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The range of the basic

tan

function is

- \infty < tan (2 θ - \frac{11 π}{6}) < \infty

- \infty < tan (2 θ - \frac{11 π}{6}) < \infty

Add to the edges of the range:

- 1

- \infty < tan (2 θ - \frac{11 π}{6}) - 1 < \infty

Therefore the range is

- \infty < f (θ) < \infty

y = 3 x - 8

y = (\frac{1}{6})^{x}

f (x) = - 4 x^{2} - 6 x + 1

f (x) = 0.05 x + 25 + \frac{300}{x}

f (x) = - x^{2} + 3 x

What is the range of tan(2θ-(11pi)/6)-1 ?
The range of tan(2θ-(11pi)/6)-1 is -infinity <f(θ)<infinity