What is the critical f(x)=0.05x+25+(300)/x ?

The critical f(x)=0.05x+25+(300)/x is x=-20sqrt(15),x=20sqrt(15)

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critical f(x)=0.05x+25+(300)/x

critical points

f (x) = 0.05 x + 25 + \frac{300}{x}

x = - 2015, x = 2015

Solution steps

0.05 x + 25 + \frac{300}{x}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 2015, x = 2015, x = 0

Identify critical points not in

f (x)

domain

Domain of

0.05 x + 25 + \frac{300}{x} : x < 0 or x > 0

0.05 x + 25 + \frac{300}{x}

is not defined at

x = 0

, therefore:

x = - 2015, x = 2015

f (x) = - x^{2} + 3 x

f (x) = \frac{x}{- 8 x + 3}

h (x) = 6 x + 1

y = - 5 x - 6

f (x) = \frac{e ^{x}}{6 + e ^{x}}

What is the critical f(x)=0.05x+25+(300)/x ?
The critical f(x)=0.05x+25+(300)/x is x=-20sqrt(15),x=20sqrt(15)