What is the domain of f(x)= x/(sqrt(x^2+2)) ?

The domain of f(x)= x/(sqrt(x^2+2)) is -infinity <x<infinity

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domain of f(x)= x/(sqrt(x^2+2))

domain

f (x) = \frac{x}{x ^{2} + 2}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find non-negative values for radicals:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = \frac{6}{x ^{2} + 5 x - 7}

b^{x}

f (x) = x + y = 9

2^{x - 1} + 1

f (x) = x^{2} - 2 x

What is the domain of f(x)= x/(sqrt(x^2+2)) ?
The domain of f(x)= x/(sqrt(x^2+2)) is -infinity <x<infinity