What is the critical (x^2+7)/(x-4) ?

The critical (x^2+7)/(x-4) is x=4-sqrt(23),x=4+sqrt(23)

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critical (x^2+7)/(x-4)

critical points

\frac{x ^{2} + 7}{x - 4}

x = 4 - 23, x = 4 + 23

Solution steps

\frac{x ^{2} + 7}{x - 4}

Find where

f^{'} (x)

is equal to zero or undefined

x = 4 - 23, x = 4 + 23, x = 4

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2} + 7}{x - 4} : x < 4 or x > 4

\frac{x ^{2} + 7}{x - 4}

is not defined at

x = 4

, therefore:

x = 4 - 23, x = 4 + 23

y = 9^{x}

f (x) = 9.5 x^{2} - x + 4.3

16 x^{2} - 25

f (x) = \frac{1}{x} + 8

f (x) = \frac{x - 3}{x ^{2} - 4 x + 3}

What is the critical (x^2+7)/(x-4) ?
The critical (x^2+7)/(x-4) is x=4-sqrt(23),x=4+sqrt(23)