What is the critical f(x)=x^{9/2}-4x^2 ?

The critical f(x)=x^{9/2}-4x^2 is x=0,x=(2*8^{1/5})/(81^{1/5)}

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critical f(x)=x^{9/2}-4x^2

critical points

f (x) = x^{\frac{9}{2}} - 4 x^{2}

x = 0, x = \frac{2 \cdot 8 ^{\frac{1}{5}}}{8 1 ^{\frac{1}{5}}}

Solution steps

x^{\frac{9}{2}} - 4 x^{2}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = \frac{2 \cdot 8 ^{\frac{1}{5}}}{8 1 ^{\frac{1}{5}}}

Identify critical points not in

f (x)

domain

Domain of

x^{\frac{9}{2}} - 4 x^{2} : x \geq 0

All critical points are in domain

x = 0, x = \frac{2 \cdot 8 ^{\frac{1}{5}}}{8 1 ^{\frac{1}{5}}}

f (x) = 4 x + 12

f (x) = 2 x^{2} - 3 x - 2

2 - 3 x^{2}

\frac{x + 8}{x ^{2} + x + 1}

f (x) = 3 - 2 x

What is the critical f(x)=x^{9/2}-4x^2 ?
The critical f(x)=x^{9/2}-4x^2 is x=0,x=(2*8^{1/5})/(81^{1/5)}