What is the domain of f(x)=sqrt(log_{1/3)(1-x)} ?

The domain of f(x)=sqrt(log_{1/3)(1-x)} is 0<= x<1

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domain of f(x)=sqrt(log_{1/3)(1-x)}

domain

f (x) = lo g_{\frac{1}{3}} (1 - x)

0 \leq x < 1

Interval Notation

[0, 1)

Solution steps

Find non-negative values for radicals:

0 \leq x < 1

The function domain

0 \leq x < 1

\frac{1}{∣ x ∣ + x}

f (x) = \frac{x ^{2} - 2}{x + 2}

f (x) = \frac{9 - x ^{2}}{x + 1}

(x - 3)^{3} + 4

f (x) = 16 x + 35

What is the domain of f(x)=sqrt(log_{1/3)(1-x)} ?
The domain of f(x)=sqrt(log_{1/3)(1-x)} is 0<= x<1