What is the extreme f(x)=4x^3-15x^2-18x+7 ?

The extreme f(x)=4x^3-15x^2-18x+7 is Maximum(-1/2 , 47/4),Minimum(3,-74)

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extreme f(x)=4x^3-15x^2-18x+7

extreme points

f (x) = 4 x^{3} - 15 x^{2} - 18 x + 7

Maximum (- \frac{1}{2}, \frac{47}{4}), Minimum (3, - 74)

Solution steps

f^{'} (x) = 12 x^{2} - 30 x - 18

Find intervals:

Increasing

: - \infty < x < - \frac{1}{2},

Decreasing

: - \frac{1}{2} < x < 3,

Increasing

: 3 < x < \infty

Plug

x = - \frac{1}{2}

into

4 x^{3} - 15 x^{2} - 18 x + 7 : \frac{47}{4}

Maximum (- \frac{1}{2}, \frac{47}{4})

Plug

x = 3

into

4 x^{3} - 15 x^{2} - 18 x + 7 : - 74

Minimum (3, - 74)

Maximum (- \frac{1}{2}, \frac{47}{4}), Minimum (3, - 74)

cot (x) cos (x) + csc (x) sin (2) (x)

f (x) = x^{4} - 4 x^{2} + 4

f (x) = - 3 x - 2

2 x - 3 y = - 6

1 + ln (t)

What is the extreme f(x)=4x^3-15x^2-18x+7 ?
The extreme f(x)=4x^3-15x^2-18x+7 is Maximum(-1/2 , 47/4),Minimum(3,-74)