What is the extreme f(x)=x^2-10,-2<= x<= 3 ?

The extreme f(x)=x^2-10,-2<= x<= 3 is Maximum(-2,-6),Minimum(0,-10),Maximum(3,-1)

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extreme f(x)=x^2-10,-2<= x<= 3

extreme points

f (x) = x^{2} - 10, - 2 \leq x \leq 3

Maximum (- 2, - 6), Minimum (0, - 10), Maximum (3, - 1)

Solution steps

Find the critical points:

x = - 2, x = 0, x = 3

Domain of

x^{2} - 10, - 2 \leq x \leq 3 : - 2 \leq x \leq 3

Find intervals:

Decreasing

: - 2 < x < 0,

Increasing

: 0 < x < 3

Plug the extreme point

x = - 2

into

x^{2} - 10 \Rightarrow y = - 6

Maximum (- 2, - 6)

Plug the extreme point

x = 0

into

x^{2} - 10 \Rightarrow y = - 10

Minimum (0, - 10)

Plug the extreme point

x = 3

into

x^{2} - 10 \Rightarrow y = - 1

Maximum (3, - 1)

Maximum (- 2, - 6), Minimum (0, - 10), Maximum (3, - 1)

2 x^{3} + 3 x^{2} - 180 x

f (x) = \frac{t}{t + 1}

f (x) = 4 x^{3} + 21 x^{2} + 18 x + 2

f (x) = 18 x^{\frac{2}{3}} - 6 x

What is the extreme f(x)=x^2-10,-2<= x<= 3 ?
The extreme f(x)=x^2-10,-2<= x<= 3 is Maximum(-2,-6),Minimum(0,-10),Maximum(3,-1)