What is the domain of x/(\sqrt[4]{9-x^2)} ?

The domain of x/(\sqrt[4]{9-x^2)} is -3<x<3

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domain of x/(\sqrt[4]{9-x^2)}

domain

- 3 < x < 3

Interval Notation

(- 3, 3)

Solution steps

Find non-negative values for radicals:

- 3 \leq x \leq 3

Find undefined (singularity) points:

x = 3, x = - 3

Combine real regions and undefined points for final function domain

- 3 < x < 3

y = 3 x - 7, (3, - 5)

arctan (cot (x))

x^{2} - 4 x - 45

f (x) = 5 - 4 x

2 y + 8 x = 2

What is the domain of x/(\sqrt[4]{9-x^2)} ?
The domain of x/(\sqrt[4]{9-x^2)} is -3<x<3