What is the domain of g(x)=(sqrt(9+x))/(4-x) ?

The domain of g(x)=(sqrt(9+x))/(4-x) is -9 4

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domain of g(x)=(sqrt(9+x))/(4-x)

domain

g (x) = \frac{9 + x}{4 - x}

- 9 \leq x < 4 or x > 4

Interval Notation

[- 9, 4) \cup (4, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 9

Find undefined (singularity) points:

x = 4

Combine real regions and undefined points for final function domain

- 9 \leq x < 4 or x > 4

f (x) = \frac{- 3 x ^{3}}{x - 4}

\frac{9}{x} + 5

\frac{50 e ^{t}}{2 e ^{t} - 1}

f (x) = x cos (x)

What is the domain of g(x)=(sqrt(9+x))/(4-x) ?
The domain of g(x)=(sqrt(9+x))/(4-x) is -9<= x<4\lor x>4