What is the domain of 1/(sqrt(x^2+7)) ?

The domain of 1/(sqrt(x^2+7)) is -infinity <x<infinity

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of 1/(sqrt(x^2+7))

domain

\frac{1}{x ^{2} + 7}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find non-negative values for radicals:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

3 x^{2} + 2 x - 1

f (x) = 2 x^{3} - 3 x^{2} - 72 x - 12

15 - 5 x

3 x^{2} - 12 x + 11

f (x) = \frac{5}{2} x - 2

What is the domain of 1/(sqrt(x^2+7)) ?
The domain of 1/(sqrt(x^2+7)) is -infinity <x<infinity