What is the shift f(x)=tan(2x-(2pi)/3)+5 ?

The shift f(x)=tan(2x-(2pi)/3)+5 is Phase: pi/3 , Vertical:5

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shift f(x)=tan(2x-(2pi)/3)+5

shift

f (x) = tan (2 x - \frac{2 π}{3}) + 5

Phase : \frac{π}{3}, Vertical : 5

Solution steps

f (x) = tan (2 x - \frac{2 π}{3}) + 5

g (B x - C) = tan (2 x - \frac{2 π}{3}), B = 2, C = \frac{2 π}{3}, D = 5

Therefore, the phase shift

\frac{C}{B}

\frac{\frac{2 π}{3}}{2}

\frac{π}{3}

The vertical shift

D

5

5

- \frac{7}{2 t ^{(\frac{3}{2})}}

f (x) = \frac{x}{x ^{2} - 1}

f (x) = - \frac{3}{x - 2}

f (x) = \frac{1}{2 x ^{2} - x - 6}

(0, 7), (4, 6)

What is the shift f(x)=tan(2x-(2pi)/3)+5 ?
The shift f(x)=tan(2x-(2pi)/3)+5 is Phase: pi/3 , Vertical:5