What is the domain of f(x)=\sqrt[3]{x/(x^2+6x-16)} ?

The domain of f(x)=\sqrt[3]{x/(x^2+6x-16)} is x 2

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domain of f(x)=\sqrt[3]{x/(x^2+6x-16)}

domain

x < - 8 or - 8 < x < 2 or x > 2

Interval Notation

(- \infty, - 8) \cup (- 8, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

x = 2, x = - 8

The function domain

x < - 8 or - 8 < x < 2 or x > 2

f (x) = - x + 5

x + 5 y = - 5

\frac{( x + 7 )}{x}

f (x) = x^{3} + 2 x

f (x) = \frac{1}{x ^{2} - 6 x + 11}

What is the domain of f(x)=\sqrt[3]{x/(x^2+6x-16)} ?
The domain of f(x)=\sqrt[3]{x/(x^2+6x-16)} is x<-8\lor-8<x<2\lor x>2