What is the amplitude of-1+2sin(x+pi/3) ?

The amplitude of-1+2sin(x+pi/3) is 2

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amplitude of-1+2sin(x+pi/3)

amplitude

- 1 + 2 sin (x + \frac{π}{3})

2

Solution steps

f (x) = - 1 + 2 sin (x + \frac{π}{3}), A = 2

Therefore, the amplitude |A| is

2

2

2 x - 1

f (x) = \frac{- 1 - 1 - 20 x}{10}

\frac{x ^{3}}{x ^{2} - 3 x + 2}

(- 3, - 4), (- 7, 3)

f (x) = \frac{2 x ^{2}}{3 x - 1}