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Popular >

distance (-2,0),(2,3)

Solution

distance

(- 2, 0), (2, 3)

Solution

5

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(- 2, 0)

and

(2, 3)

is

= (2 - (- 2))^{2} + (3 - 0)^{2}

Simplify

= 5

Popular Examples

inverse of sqrt(x^2-3x+2)inverse

x^{2} - 3 x + 2

range of f(x)=((x-3)^2)/(x^2)range

f (x) = \frac{( x - 3 ) ^{2}}{x ^{2}}

domain of f(x)=ln(1+((x+1))/(x+4))domain

f (x) = ln (1 + \frac{( x + 1 )}{x + 4})

extreme f(x)=x^5+5x^4 extreme points

f (x) = x^{5} + 5 x^{4}

domain of f(x)=6x+9 domain

f (x) = 6 x + 9

Frequently Asked Questions (FAQ)

What is the distance (-2,0),(2,3) ?
The distance (-2,0),(2,3) is 5