What is the range of-sqrt(2x-3)+6 ?

The range of-sqrt(2x-3)+6 is f(x)<= 6

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range of-sqrt(2x-3)+6

range

- 2 x - 3 + 6

f (x) \leq 6

Interval Notation

(- \infty, 6]

Solution steps

The range of an radical function of the form

- c a x + b + k

f (x) \leq k

k = 6

f (x) \leq 6

x^{3} + 2 x^{2} - 3 x + 1

y = lo g_{0.5} (x)

(2.6) (10.8)

\frac{( 5 t + 1 )}{t ^{3} - t ^{2} - 8 t}

(- 2, - 3), (- 5, - 5)