What is the domain of f(x)=(sqrt(x+3))/(3x-6) ?

The domain of f(x)=(sqrt(x+3))/(3x-6) is -3 2

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domain of f(x)=(sqrt(x+3))/(3x-6)

domain

f (x) = \frac{x + 3}{3 x - 6}

- 3 \leq x < 2 or x > 2

Interval Notation

[- 3, 2) \cup (2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 3

Find undefined (singularity) points:

x = 2

Combine real regions and undefined points for final function domain

- 3 \leq x < 2 or x > 2

f (x) = \frac{2 x}{( x + 1 ) ^{2}}

\frac{7 a}{( a + 1 ) ( a - 4 )}

y = lo g_{4} (x + 3)

y = \frac{1}{3 ^{x}}

f (x) = x^{3} - x^{2} - x - 3

What is the domain of f(x)=(sqrt(x+3))/(3x-6) ?
The domain of f(x)=(sqrt(x+3))/(3x-6) is -3<= x<2\lor x>2