What is the inverse of f(x)= 4/((2x-3)^2)+5 ?

The inverse of f(x)= 4/((2x-3)^2)+5 is (2sqrt(x-5)+3(x-5))/(2(x-5)),(-2sqrt(x-5)+3(x-5))/(2(x-5))

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inverse of f(x)= 4/((2x-3)^2)+5

inverse

f (x) = \frac{4}{( 2 x - 3 ) ^{2}} + 5

\frac{2 x - 5 + 3 ( x - 5 )}{2 ( x - 5 )}, \frac{- 2 x - 5 + 3 ( x - 5 )}{2 ( x - 5 )}

Solution steps

y = \frac{4}{( 2 x - 3 ) ^{2}} + 5

Replace

x

with

y

x = \frac{4}{( 2 y - 3 ) ^{2}} + 5

Solve for

y, x = \frac{4}{( 2 y - 3 ) ^{2}} + 5

\frac{2 x - 5 + 3 ( x - 5 )}{2 ( x - 5 )}, \frac{- 2 x - 5 + 3 ( x - 5 )}{2 ( x - 5 )}

x^{x}

(5.8) (3.9)

f (x) = x 10 - x^{2}

f (x) = \frac{x + 3}{x ^{2} - 6 x + 9}

What is the inverse of f(x)= 4/((2x-3)^2)+5 ?
The inverse of f(x)= 4/((2x-3)^2)+5 is (2sqrt(x-5)+3(x-5))/(2(x-5)),(-2sqrt(x-5)+3(x-5))/(2(x-5))