What is the asymptotes of f(x)=(-2x^2)/(2(x^2-3x+2)) ?

The asymptotes of f(x)=(-2x^2)/(2(x^2-3x+2)) is Vertical: x=1,x=2,Horizontal: y=-1

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asymptotes of f(x)=(-2x^2)/(2(x^2-3x+2))

asymptotes

f (x) = \frac{- 2 x ^{2}}{2 ( x ^{2} - 3 x + 2 )}

Vertical : x = 1, x = 2, Horizontal : y = - 1

Solution steps

Vertical asymptotes of

\frac{- 2 x ^{2}}{2 ( x ^{2} - 3 x + 2 )} : x = 1, x = 2

Horizontal Asymptotes of

\frac{- 2 x ^{2}}{2 ( x ^{2} - 3 x + 2 )} : y = - 1

Slant Asymptotes of

\frac{- 2 x ^{2}}{2 ( x ^{2} - 3 x + 2 )} :

None

Vertical : x = 1, x = 2, Horizontal : y = - 1

f (x) = x e^{- 9 x}

5 x + 2 y = 6

(5.1) (9.4)

(- 5, - 2), (5, 3)

\frac{( x ^{2} - 3 x - 2 )}{4 x ^{4} + 5 x - 4}

What is the asymptotes of f(x)=(-2x^2)/(2(x^2-3x+2)) ?
The asymptotes of f(x)=(-2x^2)/(2(x^2-3x+2)) is Vertical: x=1,x=2,Horizontal: y=-1