What is the range of f(t)= 4/(3-t) ?

The range of f(t)= 4/(3-t) is f(t) 0

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range of f(t)= 4/(3-t)

range

f (t) = \frac{4}{3 - t}

f (t) < 0 or f (t) > 0

Interval Notation

(- \infty, 0) \cup (0, \infty)

Solution steps

The function range is the combined domain of the inverse functions

Find the inverse function(s) of:

\frac{4}{3 - t}

Inverse of

\frac{4}{3 - t} : - \frac{4 - 3 t}{t}

- \frac{4 - 3 t}{t}

Find the domain of each inverse function

Domain of

- \frac{4 - 3 t}{t} : t < 0 or t > 0

Combine the intervals

f (t) < 0 or f (t) > 0

7 - x^{3}

5 x - 6

x - 3

f (x) = 4 x + 3 - 4

f (x) = (x + 1)^{3}

What is the range of f(t)= 4/(3-t) ?
The range of f(t)= 4/(3-t) is f(t)<0\lor f(t)>0